Pythagorean Theorem Calculator [Solves for all legs]

[Felktor]

--Code:

while true do w=io.read(print('Solve for leg c(c) or leg b/a(b)'))
if w ~= 'c' and w ~= 'b' then print'invalid' a = 'i'
end
if a ~= 'i' then ro=io.read(print'Round the answer? y/n (whole number)')
else a = 'weeee'
end
if w=='c' then a=io.read(print('Leg a?')) a=a^2 b=io.read(print('Leg b?')) b=b^2 answ=(b+a)^(1/2) if ro=='n' then print('the answer is '..answ)
else answ=math.floor(answ+.5)print('The answer is ' .. answ)
end
elseif w=='b' then print'Leg a?' a=io.read()^2 print'Leg c?' c=io.read()^2 answ=(c-a)^(1/2) if ro=='n' then print('The answer is '..answ) else answ=math.floor(answ+.5) print('The answer is ' ..answ)
end
end
end

[penis]

Lol meme

[Guy]

I rly like the "weeee" you put, lol
You can reorganize your code to be a lot neater, tho:

while true do
w=io.read(print('Solve for leg c(c) or leg b/a(b)'))
if w ~= 'c' and w ~= 'b' then
print'invalid'
else
ro=io.read(print'Round the answer? y/n (whole number)')
a=io.read(print('Leg a?'))^2
if w=='c' then
b=io.read(print('Leg b?'))^2
answ=(b+a)^(1/2)
else
c=io.read(print('Leg c?'))^2
answ=(c-a)^(1/2)
end
if ro=='y' then
answ=math.floor(answ+.5)
end
print('The answer is ' .. answ)
end
end

[Felktor]

I like the code clumped ;p